# Line slope calculator 3x-8y=-16

**Straight line given by points A[0; 2] and B[8; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.375x+2

**Canonical form of the line equation:**3x-8y+16 = 0

**Parametric form of the line equation:**

x = 8t

y = 3t+2 ; t ∈ R

**Slope:**m = 0.375

**Slope angle of line: φ =**20°33'22″ = 0.3588 rad

**X intercept:**x

_{0}= -5.3333

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.8727

**The length of the segment AB: |AB| =**8.544

**Vector: AB =**(8; 3)

**Normal vector: n =**(3; -8)

**Midpoint of the segment AB: M =**[4; 3.5]

**Perpendicular Bisector equation:**8x+3y-42.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (8; 5) ; |OB| = 9.434**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 57°59'41″ = 1.0122 rad**